Hi johnsey, I have a hard time figuring out solving 2 math problems.

Here they are:

5y - 3 = 8 + 4(y - 2) and if 7x + 3 = 5x - 5, evaluate 2x - 1.

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5y - 3 = 8 + 4(y - 2) Multiply on right side and add LIKE terms then solve.

5y-3 = 8+4y-8 the 8-8 is 0 so we get

5y-3 =4y Since the only number term, the -3, is on the left side I will move the y-terms to the right. Subtract 5y from both sides.

5y-3 -5y =4y -5y

-3 = -y Now we want to finish with y or +1y so divide both sides by -1.

-3/-1 = -y/-1 thus we get y = 3.

+++++++++++++++++++++++++++++++++++++

If 7x + 3 = 5x - 5, evaluate 2x - 1.

Solve for x first then we evaluate.

7x + 3 = 5x - 5 I will move the variable terms to the left side and the number terms to the right.

subtract 5x from both sides.

7x + 3 -5x = 5x - 5 -5x

2x+3 = -5 Now subtract 3 from both sides.

2x+3-3 = -5-3

2x=-8 so x = - 4.

now evaluate 2x - 1. let x=-4 we get 2(-4) -1 -8-1 = -9. The -9 is the answer.

Here they are:

5y - 3 = 8 + 4(y - 2) and if 7x + 3 = 5x - 5, evaluate 2x - 1.

+++++++++++++++++++++++++++++++++++++++

5y - 3 = 8 + 4(y - 2) Multiply on right side and add LIKE terms then solve.

5y-3 = 8+4y-8 the 8-8 is 0 so we get

5y-3 =4y Since the only number term, the -3, is on the left side I will move the y-terms to the right. Subtract 5y from both sides.

5y-3 -5y =4y -5y

-3 = -y Now we want to finish with y or +1y so divide both sides by -1.

-3/-1 = -y/-1 thus we get y = 3.

+++++++++++++++++++++++++++++++++++++

If 7x + 3 = 5x - 5, evaluate 2x - 1.

Solve for x first then we evaluate.

7x + 3 = 5x - 5 I will move the variable terms to the left side and the number terms to the right.

subtract 5x from both sides.

7x + 3 -5x = 5x - 5 -5x

2x+3 = -5 Now subtract 3 from both sides.

2x+3-3 = -5-3

2x=-8 so x = - 4.

now evaluate 2x - 1. let x=-4 we get 2(-4) -1 -8-1 = -9. The -9 is the answer.

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